My First Proof
Every Wednesday in Abs. Math, a student from the class is required to volunteer to write their proof on the board and be criticized. I found the courage to be the first volunteer. What was I thinking?! So I did .. and here it is ...
THM: The sum of any three consecutive intergers is a multiple of 3.
PROOF: Let k, k+1, k+2 be any three consecutive intergers. Thus, the sum of three consecutive intergers is k+(k+1)+(k+2) = 3k+3 = 3*(k+1). Since 3*(k+1) is divisible by 3, then for any interger k, the sum of three consecutive intergers is a multiple of 3. (MTFBWY)
Before volunteering, I thought my proof was perfect. Straight to the point, clear and correct. BUT ... while writing my proof on the board, a classmate pointed out that I read the theorem incorrectly. The actual theorem is ...
THM: The product of any three consecutive intergers is a multiple of 3.
Thanks buddy! My face didn't turn red like I thought it would ... but my leg shaked at about 100 rpms. So I sat down and took a victa. Thank you victa ... you rescued me once again!!!
THM: The sum of any three consecutive intergers is a multiple of 3.
PROOF: Let k, k+1, k+2 be any three consecutive intergers. Thus, the sum of three consecutive intergers is k+(k+1)+(k+2) = 3k+3 = 3*(k+1). Since 3*(k+1) is divisible by 3, then for any interger k, the sum of three consecutive intergers is a multiple of 3. (MTFBWY)
Before volunteering, I thought my proof was perfect. Straight to the point, clear and correct. BUT ... while writing my proof on the board, a classmate pointed out that I read the theorem incorrectly. The actual theorem is ...
THM: The product of any three consecutive intergers is a multiple of 3.
Thanks buddy! My face didn't turn red like I thought it would ... but my leg shaked at about 100 rpms. So I sat down and took a victa. Thank you victa ... you rescued me once again!!!

<< Home